Math, asked by NIASINGHANIA41, 4 months ago

Sunil bought 60 apples at Rs. 30 each. He sold 60% of the apples at Rs. 40 each and remaining at
Rs. 20.50.
1.Find his profit or loss % on the whole transaction.

Answers

Answered by nishi373
9

Answer:

hello users.....

Given that:

fruitseller bought 60 apples at the rate of ₹2 per apples

and

sold 40%of the apples at the rate of ₹2 per apple and the remaining at the rate of ₹3

we have to find

profit % = ?

solution:-

fruit seller bought 60 apples @2rs then c.p of apples = 60× 2 = 120 rs

now

he sold 40% of the Apple @2 rs

40% of 60 = 40×60/100 = 24

=> he bought 24 apples @ 2 rs

then s.p of 40% of apples = 24×2 = 48 rs

and

he sold remaining (60%) of apples @ 3 rs

here

60% of 60 = 60×60/100 = 36

=> he bought 36 apples @ 3 rs

then s.p of remaining apples = 36×3 = 108 rs

the total s.p of apples = 48+ 108 = 156 rs

=> total profit = 156 - 120 = 36 rs

now ,

we know that

profit % = profit ×100% / cost price

here

P% = 36 ×100% / 120 = 30%

hence

the profit % on selling 60 apples = 30% answer

✡⭐ hope it helps ⭐✡

Answered by ss8129519
1

Answer:

132 taka profit

Step-by-step explanation:

bought price of 60 apple at RS 30 is (60*30)=1800

60% of 60apple is( 60*60)/100=36

sold price at RS 40 each of 36 apple is (36*40)=1440

apple remains (60-36)=24

sold price at RS 20.5 of 24 apple is (24*20.5)=492

total sold price(1440+492)=1932

sold price is more than bought price

so profit is(1932-1800)=132

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