Math, asked by rudrapsb2387, 11 months ago

Sunil bought a 3 year old machine from Anil at a price of rupees 729000 its value decreases by 10 p.c.p.a. what was the price of the machine when Anil bought it

Answers

Answered by eudora
31

Price of the machine was 10,00,000 when Anil bought it.

Step-by-step explanation:

Sunil bought a 3 year old machine from Anil.

The price of machine at which Sunil bought = Rs. 7,29,000

Its value decreases by = 10 p.c.p.a.

Let the value of the machine when Anil purchased be 'x'.

Now we use the formula :

\text{Current value}=p(1-r)^t

p = purchased value, r = pcpa (10%) t = time (3 years)

7,29,000 = p(1-0.10)³

7,29,000 = p(0.9)³

7,29,000 = p × 0.729

p = \frac{7,29,000}{0.729}

p = 10,00,000 Rs.

Price of the machine was 10,00,000 when Anil bought it.

Learn more about depreciation : https://brainly.in/question/12922032

Answered by pqr1843
23

Answer:

1000000

Step-by-step explanation:

Given : Sunil bought 3 years old machine

for 729000

It's value decreased by 10 % p.a

To find : Price of machine when anil bought it

A = p × ( 1 + R/100)^N

729000 = p × (1 + (-10)/100)³

729000 = p × ( 1 + (-1)/10)³

729000 = p × (9/10)³

729000 = p × 9/10 × 9/10 × 9/10

729000 = p × 729 /1000

729000/729 × 1000 = p

1000000 = p

Price of machine when Anil bought it = 1000000

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