Question

Sunil bought a 3 years old machine form Anil at a price of RS 729000. Its value decrease by 10 p.c.p.a. what was the price of the machine when Anil bought it?

Answer 1

Answer:

8,01,900

Step-by-step explanation:

The machine value gets reduced 10% every year so 3 years ago the value would have been +30% of 7,29,000 hence when anil bought it the price was 7,29,000+30%=8,01,900

Answer 2

$\small{\textsf{\textbf{\underline{\underline{The price of the machine when Anil bought it is (2) Rs 10,00,000. \::}}}}}$

Step-by-step explanation:

Step-by-step explanation:Given that:

• Sunil bought a 3-year-old machine from Anil for Rs 7,29,000.
• Its value decreases by 10% compounded per annum.

To Find:

• What was the price of the machine when Anil bought it?

Formula used:

• In compound interest.
• A = P(1 ± R/100)ᵀ

Where,

• A = Amount
• P = Principal
• R = Rate of interest
• T = Time
• + = For increased rate
• – = For decreased rate

Let us assume:

• The price of machine for Anil be x.

We have:

• Time = 3 years
• Amount = Rs 7,29,000
• Rate = 10% c.p.a
• Principal = x

Finding the price of the machine:

⟶ 729000 = x(1 - 10/100)³

⟶ 729000 = x(1 - 0.1)³

⟶ 729000 = x(0.9)³

⟶ 729000 = x × 0.9 × 0.9 × 0.9

⟶ 729000 = 0.729x

⟶ x = 729000/0.729

⟶ x = 1000000

∴ The price of the machine = Rs 10,00,000.