Question

Sunil invested ₹ 8192 at the rate of 12.5% per annum compounded anually .he received ₹ 13122 after n years.find the value of n.

Answer 1

$\sqrt{13122 \div 8192 } = 225 \div 1000$

Answer 2

Answer: The value of n is 4 years.

Step-by-step explanation:

Since we have given that

Principal = Rs. 8192

Rate of interest = 12.5%

Amount = Rs. 13122

We need to find the number of years after which it becomes Rs. 13122.

So, we will use "Compound interest":

$A=P(1+\dfrac{r}{100})^n\\\\13122=8192(1+\dfrac{12.5}{100})^n\\\\\dfrac{13122}{8192}=(1+0.125)^n\\\\1.601806641=(1.125)^n\\\\(1.125)^4=(1.125)^n\\\\n=4$

Hence, the value of n is 4 years.