Question

Sunil is standing between two walls. The wall closest to him is at a distance of 360 m. If he shouts, he hears the first echo after 4 s and the another after another 2 seconds.
1. What is the velocity of sound in the air?
2. What is the distance between two walls?
........and is (1= 330 m/s; 2= 1650m) please explain this answer

Answer 1

1. distance between sunil and the closest wall=360m
time taken for echo to be heard=4s
velocity= 2×distance/time
velocity=2×360/4
velocity=180m/s

2.let 2x be the distance between sunil and the second wall because sound is reflected back from the wall
time taken for the second echo to be heard=4+2=6s
2x=velocity×time
2x=180×6
2x=1080
x=1080/2
x=540m

Now total distance or the distance between both the walls=distance between sunil and closest wall+distance between sunil and the second wall
=360m+540m
=900m

hope this helps you....

Answer 2

⏬⏬Here is the answer ⏬⏬


⭐⭐ → 1)180m/s⭐⭐

⭐⭐→ 2)900m ⭐⭐


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