Math, asked by mail2shital1982, 1 year ago

Sunil purchased 12 1/2 litres of juice on Monday and 14 3\4 litres of juice on Tuesday. how many litres of juice he purchased together in two days ​

Answers

Answered by shilpashree71685
29

Answer:

Step-by-step explanation

Sunil purchased juice on Monday=12 1/2

Sunil purchased juice on Tuesday=14 3/5

Sunil purchased juice on both days=12 1/2+14 3/5

=25/2+73/5

( You can use cross multiplication or LCM)

=125+146/10

=271/10=27 1/10

Answered by halamadrid
2

Given,

Sunil purchased 12\frac{1}{2} liters of juice on Monday and 14\frac{3}{4} liters of juice on Tuesday.

To find,

How many liters of juice did he purchase together in two days.

Solution,

Juice purchased by Sunil on Monday =  12\frac{1}{2} liters.

Juice purchased by Sunil on Tuesday =  14\frac{3}{4} liters.

Hence, total juice purchased together in two days =  12\frac{1}{2} liters + 14\frac{3}{4} liters.

Now,

⇒    12\frac{1}{2} liters + 14\frac{3}{4} liters.

⇒   12 + \frac{1}{2} + 14 + \frac{3}{4} liters.

⇒   26 + (\frac{1}{2}+\frac{3}{4}) liters.

⇒   26 +\frac{(2 + 3)}{4} liters.

⇒   26 + 5/4 liters.

⇒   27\frac{1}{4}. liters.

Hence, the total juice purchased together in two days by Sunil is 27\frac{1}{4}. liters.

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