Math, asked by chunnidevi96, 11 months ago

sunil takes 2 round of a rectangular garden 115m long and 95m broad .shakil takes 5 rounds of a square garden whose side is 55m.who has covered more distance and how much more?​

Answers

Answered by Anonymous
30

Here is your answer dear friend:- ❤️ ️ ❤️

Sahil distance:

Perimeter of rectangular garden :-2×(l+b)

=2×(115+95)

=2×210

=420 m

Shakil distance:

Perimeter of square:-4×S

=4×55

=220m

=Distance of five rounds:

=5×220

=1100 m

=1100 m - 420 m = 680 m

Thus,Shakil cover 680 m more distance than Sahil.....

Hope it helps you ❤️

Answered by Anonymous
7

Distance covered by sunil

=number of round * perimer of the ground

=2*perimeter of ground

perimeter of rectangle ground =2(l+b)

perimeter of rectangle ground =2(115+95)

=2*210m

=410m

Distance covered by sunil=2*410m

=820m

Distance covered by shakil

distance coverd = perimeter*no.of rounds

=4*side *5

=4*55*5

=1100m

Comparison between distance of both the persons

Distance covered by sunil=820m

Distance covered by shakil=1120m

as 1120 is more than of 820 therefore distance covered by shakil which is 1120m is more

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