Question

) Sunil takes 5 days more than Anil to complete a certain work. 4 days after starting
the work, Anil left the work. The remaining work was done by Sunil in 5 days.
Find how many days each will take to complete the work.​

Answer 1

Answer:

Let Anil takes x number of days to complete the work

⇒1 day =x1 of the work.

Sunil takes 5 more days than Anil to complete the work.

⇒x+5 days

⇒1 day =(x+5)1 of the work

Together:

1 day =x1+x+51

1 day =x(x+5)(x+5+x)

1 day =(x2+5x)(2x+5) of work done

To find 4 days of work done:

1 day =(x2+5x)(2x+5)

4 days=(x2+5x)4(2x+5) 

4 days =(x2+5x)(8x+20) of work done

To find the amount of work left to be done:

Work left =1−(x2+5x)(8x+20)

Work left =(x

Step-by-step explanation:

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