Math, asked by shreharisiva, 9 months ago

Sunita is half the age of her mother Geeta. Find their ages (i) after 4 years? (ii) before
3 years?

Answers

Answered by maddymenon2910

13

Answer:

Step-by-step explanation:

Sunita ‘s age = x

Her mother Geeta ‘s age = 2x

Age after 4 years :Sunita : x + 4

Geeta: 2x + 4

Age before 3 years = Sunita: x -3

Geeta: 2x-3

Answered by samruthaasaravanan

1

Answer:

Step-by-step explanation:

Step-by-step explanation:

Sunita ‘s age = x

Her mother Geeta ‘s age = 2x

Age after 4 years :Sunita : x + 4

Geeta: 2x + 4

Age before 3 years = Sunita: x -3

Geeta: 2x-3

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