Question

Sunita is twice as old as Ashima. If six years is subtracted from
Ashima's age and four years added to Sunita's age, then Sunita
will be four times Ashima's age. How old were they two years
ago?​

Answer 1

Step-by-step explanation:

Let sunita's age be x

and Ashima's age be y

According to question....

x = 2y........ (1)

(y-6)4 = x+4

4y -24 = x +4

x -4y = -28........ (2)

From (1)=>

y = 2x

x -4y = -28

2y -4y = -28

-2y = -28

(y = 14)

Put y = 14 in (1)

2y = x

14× 2 = x

(x = 28)

(x, y) = (28,14) is your answer

Sunita's age = 28

Ashima's age = 14