Sunita is twice as old as Ashima.If six years is subtracted from Ashimas age and four years added to Sunitas age,then Sunita will be four times Ashimas age.How old were they 2 years ago?
Answers
Answered by
9
Let Sunita's age be x and Ashima's age be y
x=2y first equation
(x+4)=4(y-6) second equation
x+4=4y-24
x-4y=-28
Putting the value of x from equatio
x=2y first equation
(x+4)=4(y-6) second equation
x+4=4y-24
x-4y=-28
Putting the value of x from equatio
aryan014:
sorry it went in middle
i dont think urs is correct bro!!
Answered by
6
let ashima be x years old so now Sunita is 2x years old . if 6years i.e x-6 and x+4 .
then x+2= 4x
2= 4x-x
2 =3x
x=
then x+2= 4x
2= 4x-x
2 =3x
x=
Attachments:
my mistake
then 2x+4=4(x-6)
yah now it is right
2x+4= 4x-24
=4+24=4x-2x
=28=2x
x=28/2=14
so two years back x-2= 12 and sunita will be 2x-2= 28-2= 26
done
hmm nice one
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