Question

Sunita is twice as old as her brother, In 6 years time , the sum of their ages will be 39. What are their ages now?

Answer 1

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Sunita is twice as old as her brother, In 6 years time, the sum of their ages will be 39. What are their ages now?

Let the age of Sunita's brother be = x

Then, Sunita's age will be = 2 x

According to the question,

in 6 years of time, the sum of their ages will be 39.

= > x + 6 + 2 x + 6 = 39

= > 3 x + 12 = 39

= > 3 x = 39 - 12

= > 3 x = 27

= > x = 27 / 3

= > x = 9

Therefore, the present ages of Sunita and her brother are:-

Brother,

= x

= '9'

Sunita,

= 2x

= 2 x 9

= '18'
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Answer 2

Sunita's age is 18 years and her brother's age is 9 years  

Given:

Sunita is twice as old as her brother, In 6 years' time, the sum of their ages will be 39.

To find:

What are their ages now?

Solution:

Let x be Sunita's brother's age

From the data Sumita's age is twice of her brother

Sunita's age = 2x

After 6 years, Sunita and her brother's age will be

=> Sunita's age = 2x + 6

=> Sunita's brother's age = x + 6

From the data in 6 years sum of their ages will be 39 years

=> 2x + 6 + x + 6 = 39

=> 3x + 12 = 39

=> 3x = 27  

=> x = 9 years

Hence, Sunita's brother's present age is 9 years

Sunita's age, 2x = 2(9) = 18 years

Therefore,

Sunita's age is 18 years and her brother's age is 9 years  

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