Question

Sunitais as twice as old as Ashima. If six years is subtracted from Ashima's age and 4 years added to Sunitas age, then Sunita will be four times Ashima’s age. How old were they two years ago?

Answer 1

Step-by-step explanation:

Let the present age of Ashima be ‘x’ years The present age of Sunita is 2x years Ashima’s new age = (x – 6) years Sunita’s new age = (2x + 4) years So, (2x + 4) = 4 (x – 6) 2x + 4 = 4x – 24 2x – 4x = -24 – 4 -2x = -28 x = -28/-2 = 14 ∴ Age of Ashima is x years = 14 years Age of Sunita is 2x years = 2(14) = 28 years

Two years ago, age of Ashima is 14 – 2 = 12 years, age of Sunita = 28 – 2 = 26 years

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Answer 2

Answer:

Two years ago,Sunuta's age is 26 years and Ashimas age is 12 years

Step-by-step explanation:

That's your answer.