Math, asked by DHRUVG3964, 11 hours ago

Suppose 2 households are randomly selected from the 80 households. Find the probability that both households are satisfied with their purchase.

Answers

Answered by Phulara
0

Answer:

Consider that 80 households purchased a television. The customers were surveyed. Results found that 64 households were satisfied with their purchase and 16 households were dissatisfied. Suppose 2 households are randomly selected from the 80 households. Find the probability that both households are dissatisfied with their purchase. Round to four decimal places. (2 points) Define A = first household selected is dissatisfied Define B = second household selected is dissatisfied.

Answered by мααɴѕí
1

Answer:

We're told that a company's long, more needs no repairs for the 1st 2 years of ownership for 80% of the customers who buy it. And we're also told that we took a sample of 100 of such customers and found that only 70 of them headlong more is that made of two years of that repair. And so we're asked to calculate the probability of getting an outcome at least as low as ours. That's an outcome of 70 in a sample of 100. So a lot more either can or will not make it two years without maintenance without repairs. So that's that's, Ah, binary outcome. So we can consider this to be a binomial distribution, and let's say a success is the lawnmower makes it two years without repair. So that's key. And we're also told he assumed that that figure of 80% is correct. So P is equal to 0.80 and the number of trials is 100 because it's sample of 100. So the question is, what is the probability that 70 or less we'll make it two years without repair out of 100. And so you can calculate this probability in excel using the Bynum function. So if we go to a sound, we have equals. Do you? I n o m dot the i s t And then the number of successes 70 the number of trials 100. The probability of success is 0.8 and cumulative is true because we're looking for the key middle of cumulative probability. So that comes out to 0.11 to you. And you may notice that this this number is a little bit different from the answer in the back of the textbook because in the back of the textbook, they used the normal approximation to solve this problem. But this answer here is actually is exact because we use the binomial distribution probability.

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