Suppose 2% of the items made in a factory are defective. Find the probability that there are (a) 3 defective items in a sample of 100, and (b) no defective item in a sample of 50. 5 5. Define
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Answer:
p(defective) =0.02
p (not defective) = 0.98
a) (0.98)^47 * (0.02)^3 = 0.38692 * 0,000008 = 3.09 * 10^-6
or 0.000309%
The order does not come into play here, any 3 bulbs can be defective.
b) The chance for no defective bulbs in a sample of 50:
(0.98)^50, or about 0.36417 or 36.42%
Step-by-step explanation:
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