Suppose a and b gene shows incomplete linkage and shows 40% recombination then find out the ratio of gamete in F1 generation by crossing ++/++ gene containing plant with ab/ab gene containing plant :-
(1)++ 20% : ab 20% : + b 20% : a + 40%(2)++ 50% : ab 50%(3)++ 25% : ab 25% : b 25% : a + 25%(4)++ 30% : ab 30% : + b 20% : a + 20%
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The correct answer is (4) option.
40℅ recombination means new genotype formed will be +b and a+ and this 40℅ will be distributed equally in both genotype.And remaining 60℅ will be distributed equally among parental genotype.
40℅ recombination means new genotype formed will be +b and a+ and this 40℅ will be distributed equally in both genotype.And remaining 60℅ will be distributed equally among parental genotype.
Anonymous:
Is my answer correct?
yup...
:)
Following progeny are obtained by a test cross of F1 flies +a/+b
++/ab = 10
ab/ab = 10
+b/ab = 40
a+/ab = 40
What will be the distance between linked give :-
(1)82 cm(2)20 cm(3)18 cm(4)40 cm
++/ab = 10
ab/ab = 10
+b/ab = 40
a+/ab = 40
What will be the distance between linked give :-
(1)82 cm(2)20 cm(3)18 cm(4)40 cm
will you plzz solve this?
I will try!!
thnks
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