suppose a boy run a distance of 100m in 50 sec is going from his home to shop in east direction.calculate the speed and velocity
Answers
hey mate here the starting point and the final point is different and is in straight line so
distance = displacement
hence,
speed = velocity.
speed = distance/ time
= 100/50 = 2 m/sec
speed = velocity = 2 m/sec
Given : the boy first runs a distance of 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from the shop to reach back home from where he started
( complete Question)
To Find:
What will be the displacement of the boy?
(i) 200 m (ii) 0 m (iii) 150 m (iv) -200 m
Find the average speed of the boy.
(i) 1 m/s (ii) 2 m/s (iii) 3 m/s (iv) none of these
c. Find the velocity of the boy.
(i) 10m/s (ii) 4m/s (iii) 0 m/s (iv) 2 m/s
Solution:
Displacement = Final Position - Initial Position
as boy returns back to original position
Hence Final Position - Initial Position = 0
=> Displacement = 0 m
velocity = Displacement / Time
=> Velocity = 0/(50 + 50) = 0 m/s
Average Speed = Total Distance / Total Time
=>Average Speed = (100 + 100)/(50 + 50)
=> Average Speed = 2 m/s
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