Question

Suppose a charge +q on earth's surface and another charge +q charge is placed on the surface of the moon. Calculate the value of q required to balance the gravitational attraction between earth and moon

Answer 1

Force of attraction is directly prop to product of their masses and inversely prop to square of distance between them. ... F= (G m(1) x m(2))/ R^2, where G is the universal gravitational constant, m(1) is the mass of the earth, m(2) is the mass of the moon, and R is the distance between them, center to center (squared). Plz mark me in brain list

Answer 2

Answer:q≈+5.64*10^13C

Explanation:F(gravitational)=

GMeMm/r^2

Me -mass of earth

Mm- mass of moon

r -distance between earth and moon

F=308.83*10^35 /r^2

Now,

F(electrostatic)=9*10^9*q^2 /r^2

But r is same

q=√34.315*10^26

q≈5.64*10^13C