Suppose a cyclist travels 15 kilometers during the first hour. Then the cyclist travels 33 kilometers during the next 2 hours. What is the cyclist’s average speed?
Answers
Explanation:
Distance = Speed × Time.
Answers: The average speed of the cyclist who travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour is 0.6 km/hr or 1/6 m/s.
To find the average speed we need to use the relation:
Average speed = Total distance traveled/ Total time taken
Let's now consider the conditions given in the question to find the required value.
Explanation:
Let's find the total distance traveled and the total time taken.
The total distance travelled = 1 km + 0.5 km + 0.3 km = 1.8 km.
Total time taken = 1 hr + 1 hr + 1 hr = 3 hr
Now, Average speed = Total distance traveled/ Total time taken
or, Average speed = 1.8/3 = 0.6 km/hr
Now let's convert km/hr to m/sec
Since we know 1 km = 1000 m and 1 hr = (60 × 60) s = 3600 s
Therefore, 1 km/hr = 1000m/3600s
So 0.6 km/hr = 0.6 × 1000/3600 m/s
= (0.6 × 1000)/3600 m/s
= 600/3600 m/s
= 1/6 m/s
Therefore, the avergae speed of the cyclist is 0.6 km/hr or 1/6 m/s.