Question

suppose a men stand
one side of canal there is a tree on the other side of canal man is looking at the top of tree and make an angle of elevation in 45 degree find the width of Canal​

Answer 1

Answer:

1. Correct option isA 10sqrt(3) * m 10 mLet AB be the breadth of the river and BC bethe height of the tree which makes a angle of 60^ at a point A on the opposite bank.Let D be the position of the person afterretreating 20 m from the bank.Let AB = x metres and BC = h metres.We know, tan(theta) = Opposite / AdjacentFrom right Zed triangle ABC and DBC, have * tan 60 degrees = (BC)/(AB) we and tan 30 degrees = h/(20 + x); Rightarrow sqrt 3 = h x and 1 sqrt 3 = h x+20; h=x sqrt 3 and h= x+20 sqrt 3; Rightarrow x sqrt 3 = x+20 sqrt 3 Rightarrow3x=x+20 Rightarrow x=10m Putting x=10 in h= sqrt 3 x, we get h = 10sqrt(3) = 17.32m Hence, the height of the tree =17.32 m and