Question

Suppose a particle moving in three-
dimensions has a position vector
r = (4 +2t)i+(3+4t)j +(2-2t–3t²)k
where distance is measured in meters and time in seconds. Mark the incorrect statement
1)instantaneous velocity vector is
2i + 4j - (2+6t)k
2) instantaneous acceleration is -6k
3) at t=0 velocity vector is 2i + 4j - 2k
4) at t=0 acceleration is zero

This is a physics question .

Answer 1

Answer:

r = (4 +2t)i+(3+4t)j +(2-2t–3t²)k where distance is measured in meters and time in seconds. Mark the incorrect statement 1)instantaneous velocity

Step-by-step explanation:

Answer 2

Answer:

Substituing the values for t, the option (3) remains incorrect. Using the formula to find the velocity of the position vector.

Step-by-step explanation:

The formula for a particle's position vector as just a function of the time is R = 4sin(2t)i+4cos(2t)j, where R is measured in metres, t is measured in seconds, and I and j stand for unit vectors along the x- and y-axes, respectively.

The position vector is a vector that represents a particular point's position or location with reference to any arbitrary point of reference, such as the origin. The direction of a position vector is always a direction from that vector's origin to a certain location.

The unit vectors in the x, y, and z axes are I j, and k respectively. The unit vector with in x axis' direction is the unit vector.

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