Suppose a2,a3,a4,a5,a6,a7 are integers such that 5/7 = a2/2! + a3/3! + a4/4! + a5/5! + a6/6! + a7/7! Then what is a2+a3+a4+a5+a6+a7
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common difference, d=a2-a1 =1/4-(-1) =1/4+1 =5/4
next 4 terms are a4,a5,a6,a7
here a4= a+3d= (-1)+3(5/4) =11/4
a5=a+4d=(-1)+4(5/4) =4
a6=a+5d=(-1)+5(5/4) =21/4
a7=a+6d=(-1)+6(5/4)= (15/2)-1 = 13/2 or 26/4
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