Question

Suppose ABCD is a rectangle. Using RHS theorem, prove that triangles ABC and ADC are congruent.

Answer 1

Two sides and an included angle of triangle ABC are congruent to two corresponding sides and an included angle in triangle CDA. According to the above postulate the two triangles ABC and CDA are congruent.

Answer 2

Answer:

Step-by-step explanation:

Assume ABCD is a rectangle in which AC is a Diagonal.

To prove: Δ ABC ≅ Δ ADC by R.H.S. theorem.  

We know that,  

To prove a triangle by R.H.S. theorem we need a Right angle, Hypotenuse and a side.

Process:- In Δ ABC and Δ ADC

∠ ABC ≅ ∠ ADC (each 90°)

AC = AC (common hypotenuse)

AB = DC ( opposite side of rectangle are equal)

Hence Δ ABC ≅ Δ ADC by R.H.S. congurency. (Proved)