Question

Suppose all the electrons of 100 g water are lumped together to form a negatively charged particle and all the nuclei are lumped together to form a positively charged particle. If these two particles are placed 10 0 cm away from each other, find the force of attraction between them. Compare it with your weight.

Answer 1

Answer:

hy Mate

Explanation:

Molecular weight of H2O=2×1×16=16

No. of electrons present in on molecular of H2O=10

18gm of H2O has 6.023×1023 molecular

18gm of H2O has 6.023×1023×10 electrons.

100gm of H2O has 18×1006.023×1024 electrons.

∴ number of protons= 186.023×1026

Charge of protons =181.6×10−19×6.023×1026

=181.6×6.023×107c

Charge of electrons =181.6×6.023×107c

∴ Electrical force =(10×10−2)29×10

∴ Electrical force =(10×10−2)29×109(181.6×6.023×107)×(181.6×6.023×107)

=188×6.023×1.6×6.023×1025=2.56×1025N

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Answer 2

Answer:

Answer Is Given by Xainlone856.

Explanation:

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