Suppose an astronaut lands on the moon and drops an object from a height of 4.97 m from the surface. How much time will it take to reach the moons surface
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Answer:2.24
Explanation:using formula
S=ut+1/2at2
U=0,
So.
4.97=0+1/2*10/6(gravity of moon)*t^2
(4.97*2*10)/6=t^2
5.964=t^2
2.44=t
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