Suppose an orbital may accomodate 3 electrons
then the number of elements in IV period.
(1) 18 (2) 27 (3) 12 (4) 45
Answers
Answered by
4
Answer:
27 electrons are in 4th period
Answered by
2
Answer:
answer is 12
1=3
then, 4=3×4
=12
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