Suppose f(x)=3x(x-1)/x²-3x+2 for x≠1,2,f(1)= -3,f(2)=4 then f(x) is continuous
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Let us assume that 3+5 is a rational number.
Now,
3+5=ba [Here a and b are co-prime numbers]
5=[(ba)−3]
5=[(ba−3b)]
Here, [(ba−3b)] is a rational number.
But we know that 5 is an irrational number.
So, [(ba−3b)] is also a irrational number.
So, our assumption is wrong.
3+5 is an irrational number.
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