Question

Suppose n is a positive integer such that (n^2 +
48) is a perfect square. What is the number of
such n?
मान लीजिए n इस प्रकार का एक धनात्मक
पूर्णांक है कि (n^2 + 48) एक पूर्ण वर्ग है। इस
प्रकार के की संख्या क्या है?
(a) One (b) Two ( (c) Three ( (d) Four​

Answer 1

Answer:

a) one

Step-by-step explanation:

because if we put one in place of n the answer is seven

Answer 2

Answer:

answer (c) three

Step-by-step explanation:

let x²=n²+48

(x+n)(x-n)=48

both x and n must be odd or both even

x – n = 2, x + n =24

then n=11

x – n = 4, x + n = 12

n=8/4=4

x – n = 6, x + n = 8

n=2/2=1

Thus possible values og n are 11,4, and 1

answer (c) three