suppose that 64 raindrops combine into a single drop.calculate the ratio of the total surface energy to that single drop
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- Ratio of total surface area of 64 drops to that of a single drop is 4/1
Let the radius of each drop is r .
So, total 64 drops combines to form one larger drop.
Volume of 64 drops = volume of one bigger drop
ans we know that volume of sphere is = 4/3 πr³.
So,
64 × 4/3 πr³ = 4/3 π R³ where r is the radius of smaller drops and R is the radius of bigger drop.
R = 4r
Surface energy of bigger drop is (U) = S × A = S × 4πR²
Surface area of smaller drops (U') = S × A = S × 4 π r² × 64
So , Ratio of surface energy is 4/1
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