Suppose that
F(n + 1) = F(n)+0.5 for n=1,2,3....
And, F(1)=2. Find F(101)
Answers
Answered by
1
Answer:
52
Step-by-step explanation:
it is an AP with common difference 0.5 and first term 2,
f(101) = f(1) + (n-1)d
= 2 + (101-1)(0.5) = =52
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