Math, asked by nishajoshi1298, 1 year ago

Suppose that it is 11 to 5 against to person who is now 38 years of age living all he is 73 and 5 to 3 against B now 43 living till he is 78 years. Find the chance that at least one of those persons will be alive 35 years hence. Chp-probability plz, plz fastly answer.

Answers

Answered by Anonymous
12

Answer:

Let A and B those persons  

P(A live 35 years more) = 1-11/16  

P(B live 35 years more) = 1- 5/8  

 

P( at least A or B live 35 years more) = 1-(1-P(A))(1-P(B)) = 1-(11/16)(5/8)  

= 1-55/128 = 73/128  

Answer: 73/128

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