Suppose that it is 11 to 5 against to person who is now 38 years of age living all he is 73 and 5 to 3 against B now 43 living till he is 78 years. Find the chance that at least one of those persons will be alive 35 years hence. Chp-probability plz, plz fastly answer.
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Let A and B those persons
P(A live 35 years more) = 1-11/16
P(B live 35 years more) = 1- 5/8
P( at least A or B live 35 years more) = 1-(1-P(A))(1-P(B)) = 1-(11/16)(5/8)
= 1-55/128 = 73/128
Answer: 73/128
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