Question

Suppose that you have the task of measuring the
lengths of a bridge and a rivet and come up with 9999
and 9 cm, respectively. If the true values are 10,000 and
10 cm, respectively, compute the true percent relative
error for length (%EI)& rivet(%Er)
А
a)%El =0.01 ; %Er=1
B
b)%El =0.01 ; %Er=20
с
c) %El =0.01; %Er=10
D
%El = 10; %Er=0.01​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The error for measuring the bridge is EA = |true value – approx value |

10,000 − 9999 = 1 cm and for

the rivet it is EA = 10 − 9 = 1 cm

The percent relative error for the bridge is EP = EA / true value X 100

= 1/10,000 X 100= 0.01 %

and for the rivet it is 1/10 X 100 = 10%.