Suppose the block of the previous problem is pushed down the incline with a force of 4 N. How far will the block move in the first two seconds after starting from rest? The mass of block is 4 kg.Concept of Physics - 1 , HC VERMA , Chapter 6:Friction " question number 5
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26
Solution :
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From the free body diagram;
4-4a-μR+4g Sin 30°=0--------(1)
R-4gCos 30 °=0-----------(2)
R=4g Cos30°=0
Putting the values of R in equation 1 we get :
4-4a-0.11x4g cos30+4g sin30=o
4-4a-0.11x4x10x√3/2 +4 x10 x 1/2=0
4-4a-3.81+20=0
4-4a-3.18+20=0
a=5m/s2
For the block : u=0 m/s
a=5m/s2
t=2sec
S=ut+1/2at²
S=0+1/2 (5x 4)
S=10 m
Hence the block moves 10m.
***********************************************************
From the free body diagram;
4-4a-μR+4g Sin 30°=0--------(1)
R-4gCos 30 °=0-----------(2)
R=4g Cos30°=0
Putting the values of R in equation 1 we get :
4-4a-0.11x4g cos30+4g sin30=o
4-4a-0.11x4x10x√3/2 +4 x10 x 1/2=0
4-4a-3.81+20=0
4-4a-3.18+20=0
a=5m/s2
For the block : u=0 m/s
a=5m/s2
t=2sec
S=ut+1/2at²
S=0+1/2 (5x 4)
S=10 m
Hence the block moves 10m.
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