suppose the displacement of a particle is related to a time according to expression S=ct3(cube) .what are the dimensions of the constant c.
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Answered by
19
The dimensions of S is L,time is t given s=ct^3 c=St^-3
c=LT^-3
c=LT^-3
Rubiee:
will u plz write it in detail..:)
means step wise..
c is not any physical quantity so simply by transposing d t^3 to other side we get its dimensional formula.In D.F S is represented bt lettrt L and time by letter t.This method is usually used to know for constansts only not for physical quantities. Hope that u can understand this explanation.
yeah ok Thanks..:)
Answered by
49
According to dimensional analysis.
the dimension of LHS and RHS should be same.
S = L
so, ct³ =[ L]
⇒c T³= L
⇒c =[L T^(-3)]
where L is for length, T for time and M for mass
the dimension of LHS and RHS should be same.
S = L
so, ct³ =[ L]
⇒c T³= L
⇒c =[L T^(-3)]
where L is for length, T for time and M for mass
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