Suppose the distance above the ground is represented by a positive integer,then that below the ground will be represented by negative number. If an elevator descends into a mine shaft at the rate of 6 metre per minute;what will be it's position after half an hour ?
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Answered by
11
v=-6m/min=-6m/60s=-0.1m/s
t=0.5 hr=0.5*60*60=1800s
S=v*t=-0.1*1800=-180m
Therefore the elevator will be 180 meters below the ground after half an hour.
t=0.5 hr=0.5*60*60=1800s
S=v*t=-0.1*1800=-180m
Therefore the elevator will be 180 meters below the ground after half an hour.
Answered by
15
1 minute = -6 metre
according to question ,
30 minutes = -6 * 30
= -180
so , the elevelator position would be 180 metre below the ground
according to question ,
30 minutes = -6 * 30
= -180
so , the elevelator position would be 180 metre below the ground
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