Question

Suppose the first quartile is 20, the
third quartile is 50 and Bowley's
coefficient of skewness is then the
median of the distribution is​

Answer 1

Step-by-step explanation:

I don't know sorry any other questions

Answer 2

Answer: 35

Step-by-step explanation:

Bowley's coefficient, $Sk_{n} =0$

$SK_{n}=\frac{(Q_{3} +Q_{1} -2Q_{2} )}{Q_{3}-Q_{1} }$

⇒$0=50+20-2Q_{2}$

⇒ $2Q_{2}=70$

⇒ $Q_{2} =35$

Median = $Q_{2}=35$

∴ the median of the distribution is​ 35