Question

Suppose we consider fission of a 56/26fe into two equal fragments 2813Al neceus .Is the fussion energetically possible? justify by working out Q value of the process.
Given (m) 5626fe =55.93 4944 and (m2813 Al =27.98191??​

Answer 1

Given :

⁵⁶Fe₂₆ → 2 ²⁸Al₁₃

m₁ = Atomic mass of Fe = 55.934944u

m₂ = Atomic mass of Al = 27.98191u

To find :

Is the fission energetically possible ?

Solution :

⁵⁶Fe₂₆ → 2 ²⁸Al₁₃

Q = (m₁ - 2m₂) × 931.5 MeV

Q = (55.934944 - 2 × 27.98191) × 931.5

Q = -26.902MeV

Q is negative.

Since Q is negative and hence fission is not possible.