Math, asked by lionshustle4, 8 months ago

Suppose x is a normally distributed random variable with μ = 50 and Ϭ = 3. Find a value of the random variable, call it x0, such that  P(x ≤ x0) = 0.8413 b. P(x > x0) = 0.25 c. P(x > x0) = 0.95 d. P(41 ≤ x < x0) = 0.8630 e. 10% of the values of x are less than x0. f. 1% of the values of x are greater than x0.

Answers

Answered by sjena1976
0

Answer:

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Step-by-step explanation:

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