Question

suppose you have ,3 boxeswith light bulbs.the first one contain 10 bulbs with 6 of them brokenin the second one there are 6 light bulbs and only one broken and in the third one there broken.light bulb out of eight? what is the probeblitythat if you choose a box at random and you take a lught bulbs this broken?​

Answer 1

Answer:

add 6+3

=9 answer is

9 bro

Answer 2

Answer:

Step-by-step explanation:

box 1 : broken= 6

box 2 : broken= 1

box 3: broken ?( not mentioned by u in q ; consider x)

Total broken bulbs = 7+x ; TOTAL BULBS= 10+ 6+ 8= 24

SO PROBABILITY =  7+x/24

pls mark as brainliest if it helps plsssssssss