suppose you have ,3 boxeswith light bulbs.the first one contain 10 bulbs with 6 of them brokenin the second one there are 6 light bulbs and only one broken and in the third one there broken.light bulb out of eight? what is the probeblitythat if you choose a box at random and you take a lught bulbs this broken?
Answers
Answered by
1
Answer:
add 6+3
=9 answer is
9 bro
Answered by
0
Answer:
Step-by-step explanation:
box 1 : broken= 6
box 2 : broken= 1
box 3: broken ?( not mentioned by u in q ; consider x)
Total broken bulbs = 7+x ; TOTAL BULBS= 10+ 6+ 8= 24
SO PROBABILITY = 7+x/24
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