Question

Suppose you have a 100g sample of iriduium-182, which undergoes beta decay to form osmium-182. The half-life of iriduium-182 is 15 minutes. After 60 minutes, how much iridium-182 will remain in the sample?

a
50
b
12.5
c
6.25

Answer 1

Answer:

6.25

Explanation:

N(new)=N(sample)*2^(-t/T(half life)

N=100*2^(-60/15)

N=6.25g