Suppose you have a 100g sample of iriduium-182, which undergoes beta decay to form osmium-182. The half-life of iriduium-182 is 15 minutes. After 60 minutes, how much iridium-182 will remain in the sample?
a
50
b
12.5
c
6.25
Answers
Answered by
0
Answer:
6.25
Explanation:
N(new)=N(sample)*2^(-t/T(half life)
N=100*2^(-60/15)
N=6.25g
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