Suppose you have been given this classful IP address 110.24.33.34. a. You want to create a network of 1024 (assignable) IP addresses, what will be the length of network and host part? b. Write down the subnet mask for this IP address c. Write down the Network ID for this network along with prefix length d. Write down the broadcast IP address in this network e. How many additional (extra) IP addresses do you have in this network? (Whereas the requirement is 1024 IP addresses as mentioned above)
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Answer:
Suppose you have given this classless IP address 110.24.33.34. a. You have to create a network of 1024 (assignable) IP addresses, what will be the length of network and host part? B. Write down the subnetmask for this IP address
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If you want 1024 usable IP addresses per network you will have to use a 21 bit mask, which will provide networks with 2046 usable (plus 2 for network identification and broadcast). If you use a 22 bit mask you will only get 1022 usable, which is not what you require.
So, with that in mind, starting on network 110.24.0.0, we know that each has 2048 IPs, making this one ending on 110.24.7.255 (8*256), next will be 110.24.8.0 ending on 110.24.15.255, and so on and so forth until you finally get the network to which that host belongs. It will be network 110.24.32.0 that has broadcast address of 110.24.39.255. There are several network calculators on the internet. However, knowing how to work with net masks manually is always good since sometimes you have to do calculations manually.