Math, asked by srd700028522, 8 months ago

suppose you remove the jacks, queens and kings from the deck. this leaves you with 40 cards, if the value of the remaining cards is equal to the face value ( the Ace being a value of 1), what is expected value of the remaining cards??????

Answers

Answered by Rohitwiz
0

Answer:

220

Step-by-step explanation:

A to 10 = 1+2+3+4+5+6+7+8+9+10 = 55

There are 4 suits,

4(1+2+3+4+5+6+7+8+9+10) = 4(55)

= 220

Answered by amitnrw
0

Given : jacks, queens and kings removed from the deck leaving 40 cards . considering Ace is being value of 1 .

To find : expected value of the 40 cards

Solution:

After removal of  jacks, queens and kings from the deck.

remaining cards are  1 to 10 ( 4 Each)  ( calling Ace as 1 )

Total Cards = 40

Probability of Each Cars  = 4/40  = 1/10

Expected Value  =  ∑ ( probability  * Value )

= (1/10) * 1  + (1/10)*2  + ............................................+(1/10)*9 + (1/10)*10

= (1/10) ( 1 + 2 + 3 + ...........................+ 9 + 10)

= (1/10) 10* 11/2

= 11/2

= 5.5

expected value of the remaining cards  = 5.5

or Simply

Sum of all Card / ( number of Card)

= 4(1 + 2 + ............+ 9 + 10)/ 40

= 5.5

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