Math, asked by moniG7ud1iravith, 1 year ago

Suraj gets paid Rs. 150 per hour on a week day. On weekends he gets an extra payment which is 1/3rd of the regular payment. He is fined 1/6th of his hourly pay for every mistake he makes. Suraj puts 4 whole1/2 i.e (9/2) hours on Monday, 5 whole 1/2 i.e (11/2) hours on Tuesday, 6 whole 1/2 i.e (13/2) hours on Wednesday and 5 hours on Thursday, 4 whole 1/4 i.e (17/4) hours on Friday and 3whole 1/4 i.e (13/4 ) hours on Saturday. On Tuesday he makes 2 mistakes and on Saturday he makes 3 mistakes. What are his earnings at the end of the week?

Answers

Answered by Bhawnesh
14

Answer:

Fine for 1 mistake = 1/6 ×150= Rs 25

Payment for Monday = Rs 675

Payment for Tuesday = Rs 825 - 50 ( fine for 2 mistakes) = Rs 775

Payment for Wednesday =Rs 975

Payment for Thursday =Rs750

Payment for Friday =Rs 637.50

On saturday he gets regular payment + extra payment which is 1/3 of regular payment - fine for 3 mistakes

Payment for Saturday =( 487.50+1/3

of 487.50)-75

= (487.50+162.50) - 75

= 650.00 - 75 = Rs 575

Payment for whole week = 675+775+975+750+637.50+575

=Rs 4387.50

Answered by ramakantasahoo6154
5

Answer:

Rs. 4712.50

Step-by-step explanation:

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