surds[ if x=3+√3 and xy=6,find (x+y)^2
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(x+y)^2 = X ^2 +y^ 2 +2xy
=(3+√3)^2 +(6/3+√3)^2 +2(6)
=(9+3+6√3) +(6(3-√3)/9-3)^2 +12
=12+6√3 +(3-√3)^ 2 +12
=12+6√3 +12-6√3+12
=36
.........
mark as brainliest if helped
=(3+√3)^2 +(6/3+√3)^2 +2(6)
=(9+3+6√3) +(6(3-√3)/9-3)^2 +12
=12+6√3 +(3-√3)^ 2 +12
=12+6√3 +12-6√3+12
=36
.........
mark as brainliest if helped
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