Suresh borrowed ₹ 6000 from his friend and returned ₹ 7500 after 2 years.The rate of interest is?
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Principal = ₹6000
Time = 2 years
Amount = ₹7500
S.I = ₹7500- ₹6000 = ₹1500
Rate of interest =?
We find this using two formula
1st = R = s.i×100 / P×T
2nd S.I = P×T×T/100
We use 1st formula = S.I×100/P×T
1500×100/6000×2
150000/12000
12.5 %
2nd formula = S.I = P×R×T/100
1500 = 6000× R× 2/100
1500×100 = 12000× R
R = 150000/12000
R = 12.5%
You can use any formula
Hope it helps you
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