suresh has 98 chocolates,which he divided between two friends.veer and chetan .chetan has got 12 more chocolates than veer .find the number of chocolates got by each of them..
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Answers
Answer:
question
suresh has 98 chocolates,which he divided between two friends.veer and chetan .chetan has got 12 more chocolates than veer .find the number of chocolates got by each of them..
answer
Veer = 43 ✬
✬ Chetan = 55 ✬
Step-by-step explanation:
Given:
Total number of chocolates is 98.
Chetan got 12 more than veer.
To Find:
How many chocolates each of them get ?
Solution: Let veer got x chocolates. Therefore,
➟ Chetan got = 12 more than x
➟ Chetan = (x + 12) chocolates
Now if we add Chetan's & Veer's chocolates together then we will get total number of chocolates i.e 98.
\implies{\rm }⟹ x + x + 12 = 98
\implies{\rm }⟹ 2x + 12 = 98
\implies{\rm }⟹ 2x = 98 – 12
\implies{\rm }⟹ 2x = 86
\implies{\rm }⟹ x = 86/2
\implies{\rm }⟹ x = 43
So, chocolates they got
➛ Veer = x = 43 chocolates
➛ Chetan = x + 12 = 43 + 12 = 55
Step-by-step explanation:
HEY MATE ..........
Given:
Total number of chocolates is 98.
Chetan got 12 more than veer.
To Find:
How many chocolates each of them get ?
Solution: Let veer got x chocolates. Therefore,
➟ Chetan got = 12 more than x
➟ Chetan = (x + 12) chocolates.
Now if we add Chetan's & Veer's chocolates together then
we will get total number of chocolates
i.e 98.
⟹ x + x + 12 = 98
⟹ 2x + 12 = 98
⟹ 2x = 98 – 12
⟹ 2x = 86
⟹ x = 86/2
⟹ x = 43
So, chocolates they got
➛ Veer = x = 43 chocolates
➛ Chetan = x + 12 = 43 + 12 = 55
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