Question

Suresh is three years older than amita. six years ago Suresh was four times the Amita. Find their present ages.
Please elaborate and explain.​

Answer 1

Answer:

let us assume age of suresh is X years and that of Amita be Y

X-Y=3……eq 1

and

(X-6)=4× (Y-6)

SO we get here X-4Y= -18……eq 2

multiply eq 1 by 4 and subtract from eq 2

we get -3X=-30

so, X is 10 and y is 7

age of suresh is 10 and amita is 7 years

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

Let,

Age of Amrita be x

Age of Suresh be y

According to condition-1)

⇛ Age of Suresh = Age of Amrita + 3

⇛ y = x + 3 -------equation (1)

According to condition-2)

⇛ Age of Suresh 6 years ago = 4(Age of Amrita six years ago)

Age of Suresh 6 years ago = y - 6

Age of Amrita 6 years ago = x - 6

Then,

⇛ y - 6 = 4(x - 6)

⇛ y - 6 = 4x - 24

⇛ y = 4x - 24 + 6

⇛ y = 4x - 18 -------equation (2)

Now we will see equation (1), y = x + 3 and in equation (2), y = 4x - 18. So we can say that,

⇛ x + 3 = 4x - 18

⇛ x - 4x = -18 - 3

⇛ -3x = -21

⇛ x = 7

Then y = 7 + 3 = 10

So, the age of Suresh and Amrita respectively is 10 years and 7 years.

Hope it helps!!