Question

suresh runs twice a rectangular field with length 150 m and breadth 120 m.what distance does he cover? raj runs 4 times a square field of side 70 m . what distance does he cover

Answer 1

Answer:

Suresh runs 1080 m while Raj runs 1120 m.

Step-by-step explanation:

Suresh:

perimeter of the rectangular field = 2(150+120)

= 2×270

= 540 m

Suresh runs twice around the field.

∴ distance he covers = 2×540

= 1080 m OR 1.08 km.

Raj:

perimeter of the square field = 4×70

= 280 m

Raj runs 4 times around the field.

∴ distance he covers = 280×4

= 1120 m OR 1.12 km.

HOPE IT HELPS YOU!!!

Answer 2

Suresh covers a distance of 1.08 km.

Raj covers a distance of 1.12 km.

Step-by-step explanation:

Given:

Length of the rectangular field = 150 m

Breadth of the rectangular field = 120 m

Number of times suresh runs the rectangular field = 2

We need to find the distance covered by Suresh.

Solution;

First we will find the total distance of the rectangular field which means we need to find Perimeter of the rectangular field.

Now we know that;

Perimeter of the rectangular field is 2 times sum of length and breadth.

framing in equation form we get;

Perimeter of the rectangular field = $2(150+120) =2\times 270 = 540\ m$

Now we know that;

Distance covered by Suresh can be calculated by Distance of the rectangular field multiplied number of times suresh runs the rectangular field.

framing in equation form we get;

Distance covered by Suresh = $2\times540 =1080\ m \ \ Or \ \ 1.08\ km$

Hence Suresh covers a distance of 1.08 km.

Now Given:

Number of times Raj runs the square field = 4

side of the square field = 70 m

We need to find the distance covered by raj.

First we will find the perimeter of the square field.

Perimeter of square field is equal to 4 times the side of the square field.

framing in equation form we get;

Perimeter of square field = $4\times 70 = 280\ m$

Distance covered by Raj can be calculated by Distance of the Square field multiplied number of times Raj runs the Square field.

framing in equation form we get;

Distance covered by Raj = $4\times 280 = 1120\ m \ \ Or \ \ 1.12\ km$

Hence Raj covers a distance of 1.12 km.