Math, asked by jiyamukherjee4808, 1 year ago

Suresh starting from his house, goes 4 km in the east, then he turns to his right and goes 3 km. what minimum distance will be covered by him to come back to his house

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Answered by LakshytaMahajan
3
Hii the answer is in the above image.
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Answered by harendrakumar4417
2

5 km distance will be covered by him to come back to his house.

Step-by-step explanation:

Suresh starting from his house, goes 4 km in the east, then he turns to his right and goes 3 km.

It forms a right angle with p = 3 km, b = 4 km

We have to find h which is the minimum distance will be covered by him.

By using pythagorean theorem,

h = \sqrt{p^{2} + b^{2}}\\\\h =\sqrt{3^{2}+4^{2}}\\\\h = \sqrt{9+16}\\\\h = \sqrt{25}\\\\h = 5 \ km

Hence, 5 km distance will be covered by him to come back to his house.

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