Math, asked by sakessujaangelshai, 1 year ago

Surface area of a sphere A is 300% more than the surface area of another sphere B. If the volume of sphere B is p% less than the volume of sphere A, find the value of 'p'.

Answers

Answered by toptek
5
Surface area of a sphere is given by 4 x Pi x r² where Pi = 22/7 and r = radius of sphere.

In the given problem, we can deduce that Ra = Rb√3; where Ra = radius of sphere A and Rb = radius of sphere B.

Moving to the volume of sphere given by 4/3(Pi)(r³)

Volume of sphere A = 4/3(Pi)(Ra³) = 4/3 x (Pi) x {(Rb√3)³} because as we found out above Ra = Rb√3.

Similarly, Volume of sphere B = 4/3(Pi)(Rb³)

In order to find the ratio of volumes we must divide volume of sphere B by volume of sphere A.

Therefore, [4/3(Pi)(Rb³)] ÷ [4/3 x (Pi) x {(Rb√3)³}]

Everything else cancels out and we are left with 1 ÷ 3√3 = 1 ÷ 5.196 =0.1924

Or in other words 19.24%.

It will be safe to say that the Volume of Sphere B is 80.76% (i.e. 100-19.24) less than the volume of Sphere A.

Hence value of p will be 80.76.

Answered by nalinsingh
3

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